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Remove spurious 'return' in void method wrappers.

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For some reason, only Visual Studio bothers to give a warning when you
write "return g()" inside a function f() when both f and g have void
return type.

(Of course it would be cleaner and more orthogonal if that was simply
legal C in the first place - but given that it's not, it would be nice
if more compilers let me know about it so I could fix it...)
This commit is contained in:
Simon Tatham
2019-04-06 10:12:31 +01:00
parent 77bdaa2436
commit 1bcf2a8397
3 changed files with 10 additions and 10 deletions
Download Patch File Download Diff File Expand all files Collapse all files

8
ssh.h
View File

@ -647,10 +647,10 @@ static inline void ssh_cipher_decrypt(ssh_cipher *c, void *blk, int len)
{ c->vt->decrypt(c, blk, len); }
static inline void ssh_cipher_encrypt_length(
ssh_cipher *c, void *blk, int len, unsigned long seq)
{ return c->vt->encrypt_length(c, blk, len, seq); }
{ c->vt->encrypt_length(c, blk, len, seq); }
static inline void ssh_cipher_decrypt_length(
ssh_cipher *c, void *blk, int len, unsigned long seq)
{ return c->vt->decrypt_length(c, blk, len, seq); }
{ c->vt->decrypt_length(c, blk, len, seq); }
static inline const struct ssh_cipheralg *ssh_cipher_alg(ssh_cipher *c)
{ return c->vt; }
@ -728,9 +728,9 @@ static inline ssh_hash *ssh_hash_new(const ssh_hashalg *alg)
static inline ssh_hash *ssh_hash_copy(ssh_hash *h)
{ return h->vt->copy(h); }
static inline void ssh_hash_final(ssh_hash *h, unsigned char *out)
{ return h->vt->final(h, out); }
{ h->vt->final(h, out); }
static inline void ssh_hash_free(ssh_hash *h)
{ return h->vt->free(h); }
{ h->vt->free(h); }
static inline const ssh_hashalg *ssh_hash_alg(ssh_hash *h)
{ return h->vt; }