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Patch from Kurt Roeckx: apparently on Debian amd64, the ut_time member of

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struct utmp is not equivalent to time_t (it's 32-bit). From Debian bug#265910.

[originally from svn r4459]
This commit is contained in:
Jacob Nevins 2004-08-16 09:38:12 +00:00
parent 0edefb1809
commit df66432b5d
1 changed files with 8 additions and 2 deletions
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10
unix/pty.c
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@ -97,6 +97,7 @@ static void setup_utmp(char *ttyname, char *location)
#endif
struct passwd *pw;
FILE *wtmp;
time_t uttime;
pw = getpwuid(getuid());
memset(&utmp_entry, 0, sizeof(utmp_entry));
@ -106,7 +107,10 @@ static void setup_utmp(char *ttyname, char *location)
strncpy(utmp_entry.ut_id, ttyname+8, lenof(utmp_entry.ut_id));
strncpy(utmp_entry.ut_user, pw->pw_name, lenof(utmp_entry.ut_user));
strncpy(utmp_entry.ut_host, location, lenof(utmp_entry.ut_host));
time(&utmp_entry.ut_time);
/* Apparently there are some architectures where (struct utmp).ut_time
* is not essentially time_t (e.g. Linux amd64). Hence the temporary. */
time(&uttime);
utmp_entry.ut_time = uttime; /* may truncate */
#if defined HAVE_PUTUTLINE
utmpname(UTMP_FILE);
@ -141,13 +145,15 @@ static void cleanup_utmp(void)
{
#ifndef OMIT_UTMP
FILE *wtmp;
time_t uttime;
if (!pty_stamped_utmp)
return;
utmp_entry.ut_type = DEAD_PROCESS;
memset(utmp_entry.ut_user, 0, lenof(utmp_entry.ut_user));
time(&utmp_entry.ut_time);
time(&uttime);
utmp_entry.ut_time = uttime;
if ((wtmp = fopen(WTMP_FILE, "a")) != NULL) {
fwrite(&utmp_entry, 1, sizeof(utmp_entry), wtmp);